Hello RungeZipper,
the answer is quite simple. The TurnsRatio gives you the transformation rate of the rotor in respect to the stator. Stray-inductances and resistances don't contribute to this transformation rate. They "just" cause losses. But you are probably with me that losses on the stator side won't be transformed to the rotor and vice versa. The only inductance which transforms the currents and voltages is the mutual inductance Lmd.
Another way to explain it is that to measure the TurnsRatio the stator side would be open circuited. Thus no current would flow and thus no losses in the resistances and stray-inductances.
Dietmar
QUOTE(RungeZipperer @ Jul 5 2007, 02:01 PM)

Hi,
is anyone here who is really into the stuff of electrical machines? It is a question that deals with detailed electrical engineering:
I donīt understand the model of the synchronous machine (electrical excited) especially the TurnsRatio for the excitation current.
TurnsRatio=sqrt(2)*VNominal/(2*pi*fNominal*Lmd*Ie0).
Why is only Lmd taken into account? IMHO the idle current is calculated but then I would expect the stray inductance and the stator resistance to be also taken into account.
So my suggestion is:
TurnsRatio=sqrt(2)*VNominal/(sqrt[(2*pi*fNominal*(Lmd+Ldsigma))^2 + R1^2]*Ie0).
Who can help me?
Thanks.